Math, asked by Nicey8526, 11 months ago

How many numbers between 10 and 99 have digits that differ 3?

Answers

Answered by Anonymous
19

Answer:

there are 13 numbers differ by 3 .

14,25,30,36,41,47,52,58,63,69,74,85,56,96...............

Answered by Abhijeet1589
0

The answer is 13

GIVEN

NUMBERS - 10 to 99

TO FIND

Numbers between 10 to 99 having digits that differ by 3.

SOLUTION

We can simply solve the above problem as follows;

We are given a number range = 10 to 99

We have to find out numbers that whose defference is 3

The numbers are as follows;

14 = 4-1 = 3

25 = 5-2 = 3

30 = 3-0 = 3

36 = 6-3 = 3

41 = 4-1 = 3

47 = 7-4 = 3

52 = 5-2 = 3

58 = 8-5 = 3

63 = 6-3 = 3

69 = 9-6 = 3

74 = 7-4 = 3

85 = 8-5 = 3

96 = 9-6 = 3

Total number of numbers = 13

Hence, The answer is 13

#SPJ2

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