How many numbers between 100 and 1000 are such that exactly one of the digits is 6?
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an= a+(n-1)d
996= 102+(n-1)6
996-102= (n-1)d
894/6 = (n-1)
149+1=n
n = 150
there are 150 terms
996= 102+(n-1)6
996-102= (n-1)d
894/6 = (n-1)
149+1=n
n = 150
there are 150 terms
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