Question

How many numbers between 100 and 150 are divisible by both 3, 7 and 9?
O 5
O1
O 3
O2​

Answer 1

Answer:

The first value after 101 that is divisible by 3 is 102 (3 * 34)

(You can tell if a number is divisible by 3 by adding the digits, and if you get a value greater than 10 add the digits again, and so on - if you get a value of 3, 6 or 9 when you finish doing that adding, the original number is divisible by 3).

So 102≡1+2=3 ; so 102 is divisible by 3

Step-by-step explanation:

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Answer 2

Given: Some numbers between 100 and 150 are divisible by both 3, 7 and 9.

To find: We have to find the numbers.

Solution:

The numbers are divisible by 3,7,9.

We have to determine the LCM of 3,7 and 9.

The LCM of 3, 7, 9 is-

$3 = 3 \times 1 \\ 7 = 7 \times 1 \\ 9 = 3 \times 3$

So, LCM is 63.

Given that the numbers are between 100 and 150.

So, 63 can't be the number.

The second multiple of 63 means 126 is divisible by 3,7,9.

The third multiple that is 189 exceeds 150 thus it can't be counted.

So, only one number is divisible by 3,7,9.

The correct option is 1.