How many numbers between 400-700 divisible by either 9 or 11
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Thank you for asking this question:
We will assume as the least no divisible by 9 is 405
And the most is 693
So AP will be formed
405,414,423..........................693
The formula for nth term is given by:
an=a+(n-1)d
So, 693=405+(n-1)9
288=(n-1)9
32=n-1
So, n=33
If there is any confusion please leave a comment below.
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