How many numbers between 5000 and 10,000 can be formed
using the digits 1, 2, 3, 4, 5, 6, 7, 8, 9, each digit appearing
not more than once in each number?
(a) 5 x ⁸P₃ (b) 5 x ⁸C₃ (c) 5 ! x ⁸P₃ (d) 5 ! x ⁸C₃
Answers
Answered by
1
Answer:
2520
Step-by-step explanation:
1
st
digit can be any of 5,6,7,8,9=5 ways
2
nd
digit can be any of remaining of 9 digits (excluding 1
st
digit) = 9 ways
3
rd
digit = 8 ways, 4
th
digit = 7 ways
∴ answer is 5∗9∗8∗7=2520
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