how many numbers can be formed greater than a millon with one 0 and two 3 's and two 7's and two 1's
Answers
Answered by
1
Any number of greater than a million will contain all the seven digits.
Now, we have to arrange these seven digits, out of which 2 occurs twice, 3 occurs twice and the rest are distinct.
The number of such arrangements =
2!×3!
7!
=
2!×3!
7×6×5×4×3!
=7×6×5×2=420
These arrangements also include those numbers which contain 0 at the million’s place.
Keeping 0 fixed at the millionth place, we have 6 digits out of which 2 occurs twice, 3 occurs thrice and the rest are distinct.
These arrangements also include those numbers which contain 0 at the million’s place.
Keeping 0 fixed at the millionth place, we
=6×5×2=60 ways
Hence, the number of required numbers =420–
Similar questions