Question

How many numbers can you form using the digits 1, 5, 6 and 9 without repetition

of digits such that the value of the digit 6 in all those number is 100 times the

value of the digit 6 in the number 9561?​

Answer 1

Answer:

Hey friend,

Here is the answer you are searching for,

Place value of 6 in 9561 = 10

10×100 = 1000

The numbers from the digits 1,5,6,9 having 6 at 1000 place = 6159,6195,6519,6591,6951,6915.

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