How many numbers can you form using the digits 2, 4, 6 and 9 without repetition of the digits such that the value of the digit 6 in all those numbers is 100 times the value of the digit 6 in the number 9561? Also, give the numbers.
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Answer:
6
Explanation
Nos. = 2, 4, 6, 9
Value of 6= 100*60 = 6000
Hence nos. formed=
6249, 6294, 6429, 6492, 6924, 6942
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