how many numbers contain 4^2014 , if logbase 10 ^12 = 0.3010
armies please help me with this problem
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Answer:
hope it will be helpful to you
sorry it's not in proper way
Step-by-step explanation:
Given log
10
2=0.301
log
10
2
64
=64×log
10
2=64×0.3010=19.264
⇒2 64 =10 19.264
The number of digits in 10
19 is 20 , there will be 21 digits from 1021
The number 10
19.264
lies between them
Therefore the number of digits in 10
19.264
is 20.
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