How many numbers divisible by 5 and lying in between 40000 to 50000 can be formed from the digits 0,3,4,5,8 and 9. If repetition of digits is allowed
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How many numbers divisible by 5 and lying between 3000 and 4000 can be formed from the digits 3,4,5,6,7 and 8, no digit being repeated in any number?
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3,4,5,6,7,8
The number is divisible by 5 so the last digit can be 5 one-ways
The number should be between 3000 and 4000 so the first digit can be 3 in one-ways
Since repetition is not allowed second and third digit can be in 4 and 3 ways
so total ways =1×4×3×1=12
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