How many numbers given below leaves a remainder of 1 when divided by 3?
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Explanation:
As the number(lets say N) leaves a remainder 1 when divided by 3
Therefore, N = 3Q + 1
Now when Q is divided by 2, it leaves a remainder 1
Therefore, Q = 2I + 1
Now, putting this value of Q in the first equation, we get
=> N = 3( 2I + 1) + 1
=> N = 6I + 4
Therefore, N/6 = (6I/6) + (4/6)
6I is a multiple of 6 so it will leave the remainder 0, whereas 4 on division by 6 will leave the remainder as 4 itself.
Hence, the remainder will be 0+4 = “4”.
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