How many numbers greater than 1000000 can be formed by using the digits 1,2,3,4,0,5,3 ?
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Answer:
number begin with 1
The remaining digit to be arranged will be 0,2,2,2,4,4
Here three 2s and two 4s
Since digit are repeating hence we use this formula=
p
1
!p
2
!p
3
!
n!
Number of remaining digit=6
Thus, n=6
Since three 2s and two 4s
and p
1
=3, p
2
=2
The number of numbers beginning with 1=
p
1
!p
2
!
n!
=
3!2!
6!
=
3!×2×1
6×5×4×3!
=60
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