How many numbers greater than 23,000 can be formed using the digits 1, 2, 3, 4, 5 if
repetition of digits is allowed ?
(April 2010)
step by step explanation please
Answers
Step-by-step explanation:
if u have basic knowledge of p&c , then I hope u will understand this
Answer: 90 Number can be formed.
Step-by-step explanation:
The possible numbers can be formed greater than 23,000
Case 1 : Numbers Starting with 23 or 25 or 26
Fix 2 with inside the 1st region and 3 with inside the 2nd region. Other digits may be organized in last three locations in 3!= 3x2x1 = 6 ways.
Similarly we will calculate for numbers beginning with 25/26 (can be 6 in every of the cases).
Case 2 : Numbers Starting with 3 or 5 or 6
If we restoration three with inside the 1st region, different digits may be organized in remaining four locations in 4!= 4x3x2x1 = 24 ways.
Same for numbers beginning with 5&6 (can be 24 in every of the cases).
So, overall wide variety of numbers=6++6+6+24+24+24=90