Math, asked by sachdevtavleen8874, 1 year ago

How many numbers greater than 24,000 can be formed by using digits 1,2,3,4,5 when repitation is not allowed?

Answers

Answered by TooFree
28

Condition 1 : Number must be greater than 24,000

Condition 2: No repeats


If the digit in the ten thousands place is 2:

Number of possible digit for ten thousands place = 1

(That is, the digit 2)

Number of possible digit for thousands place = 2

(They are the digit 4 or 5)

Number of possible digit for hundred place = 3

(They are any digits not used yet)

Number of possible digit for tens place = 2

(They are any digits not used yet)

Number of possible digit for ones place = 1

(They are any digits not used yet)


Possible combinations = 1 x 2 x 3 x 2 x 1 = 12


If the digit in the ten thousands place is 3, 4, or 5:

Number of possible digit for ten thousands place = 3

(That is, the digit 3, 4, or 5)

Number of possible digit for thousands place = 4

(They are any digits not used yet)

Number of possible digit for hundred place = 3

(They are any digits not used yet)

Number of possible digit for tens place = 2

(They are any digits not used yet)

Number of possible digit for ones place = 1

(They are any digits not used yet)


Possible combinations =3 x 4 x 3 x 2 x 1 = 72


Find total possible combination:

Total combination = 12 + 72 = 84


Answer: There are 84 possible combinations

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