Question

How many numbers greater than a million can be formed with the digits 2, 3, 0, 3, 4, 2, 3?

Answer 1

many as there at is infineate

Answer 2

Answer:

Total numbers greater than 1 million = 1492992000

Step-by-step explanation:

In the given question,

The possible number of digits which can be used are 2, 3, 0, 3, 4, 2, 3.

So,

We need to get the number greater than 1 million = 100,00,00

So,

Possible number for 1st digit = 6

Possible number for 2nd digit = 6

Possible number for 3rd digit = 5

Possible number for 4th digit = 4

Possible number for 5th digit = 3

Possible number for 6th digit = 2

Possible number for 7th digit = 1

Also,

Repeated numbers,

Digit 2 = 2 times

Digit 3 = 3 times

So,

Possible number of cases where r are repeated are given by,

$\frac{n!\times m!\times o!}{r!}$

So,

Possible number of cases here are,

$Number\ of\ digits=\frac{6!\times 6!\times 5! \times 4! \times 3!\times 2!}{2!\times 3!}=6!\times 6!\times 5! \times 4!\\Number\ of\ digits=1492992000$

Therefore, total numbers greater than 1 million with the possible number of digits are 1492992000.