Math, asked by puransingh87950gami, 1 month ago

How many numbers in all do we have with(i) 5 digits (ii) 3 digits (iii) 6 digits ​

Answers

Answered by LaRouge
0

Answer:

(i)

Largest number of 5 digit = 99999 largest number of 4 digits = 9999

Required number = 99999 - 9999 = 90,000

So, 90,000 numbers are there in all.

(ii)

For calculating the numbers containing 3 digits, we can see the range of 3 digits numbers from [100, 999].

So, total number of 3 digit numbers will be:

(Greatest 3-digit number-smallest 3-digit number) + 1

=(999−100)+1

=899+1=900

(iii)

There are 9,00,000 (nine lakh) 6-digits numbers in all.

Step-by-step explanation:

hope help uh ❤❤❤❤

Answered by kunchapulaxmi0
0

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