Question

How many numbers in the sequence -1, -5/6, -2/3,.... 10/3?​

Answer 1

Answer:

n = 27.

Step-by-step explanation:

Given:

a = -1

d = t(n) - t(n - 1)

=> t(2) - t(1)

=> -5/6 -(-1)

=> -5/6+1

=> (-5+6)/6

d = 1/6

We know that, a(n) = a + (n - 1)d

10/3 = -1 + (n - 1)1/6

10/3 = (-6+n - 1)/6

10/3 = (n - 7)/6

After cross multiplication we get,

60 = 3(n - 7)

60/3 = n - 7

20 = n - 7

n = 20+7

n = 27

Therefore, there are 27 terms /numbers in the given sequence.