Question

How many
numbers lie between squares
of
@ 12 and 13
(6) 27 and 28
(c) 98 and 99​

Answer 1

Answer:

Solution:

(i) Since, non-perfect square numbers between n^2\ and\ \left(n+1\right)^{2\ }are\ 2nn

2

and (n+1)

2

are 2n

Here, n = 12

Therefore, non-perfect square numbers between 12 and 13 = 2n = 2 x 12 = 24

(ii) Since non-perfect square numbers between n^2and\ \left(n+1\right)^2\ are\ 2nn

2

and (n+1)

2

are 2n

Here, n = 25

Therefore, non-perfect square numbers between 25 and 26 = 2n = 2 x 25 = 50

(iii) Since, non-perfect square numbers between n^2and\left(n+1\right)^2are\ 2nn

2

and(n+1)

2

are 2n

here, n = 99

Therefore, non-perfect square numbers between 99 and 100 = 2n = 2 x 99 = 198