How many
numbers lie between squares
of
@ 12 and 13
(6) 27 and 28
(c) 98 and 99
Answers
Answered by
6
Answer:
Solution:
(i) Since, non-perfect square numbers between n^2\ and\ \left(n+1\right)^{2\ }are\ 2nn
2
and (n+1)
2
are 2n
Here, n = 12
Therefore, non-perfect square numbers between 12 and 13 = 2n = 2 x 12 = 24
(ii) Since non-perfect square numbers between n^2and\ \left(n+1\right)^2\ are\ 2nn
2
and (n+1)
2
are 2n
Here, n = 25
Therefore, non-perfect square numbers between 25 and 26 = 2n = 2 x 25 = 50
(iii) Since, non-perfect square numbers between n^2and\left(n+1\right)^2are\ 2nn
2
and(n+1)
2
are 2n
here, n = 99
Therefore, non-perfect square numbers between 99 and 100 = 2n = 2 x 99 = 198
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