Math, asked by harshithsaini1189, 9 months ago

How many numbers lie between the square of the following numbers
(i) 25; 26 (ii) 56; 57 (iii) 107;108​

Answers

Answered by anilsharma261972
17

Step-by-step explanation:

Given, two numbers 56 and 57 we need to find out the numbers lie between the squares of the given numbers.

Now, we have numbers lying between the square of n and (n + 1) is 2n

⇒ Numbers between squares of 56 and (56 + 1) = 2 × 56 = 112

Hence, 112 numbers lies between the square of the given numbers.

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