Math, asked by singhaftab16, 1 year ago

how many numbers lying beteeen 100 and 1000 can be formed with the digits 0,1,2,3,4,5 if the repetition of the digits is not allowed ?

Answers

Answered by Disha27
4
umm....total number of 3-digit numbers... that can be formed...
so that is 5*5*4
=100
Answered by siddhartharao77
9

From 0,1,2,3,4,5 we have 4 choices for the first place = 1,2,3,4,5 

                                                                                           = 5 numbers.


Second place also has 5 choices except 0. So again 5 numbers.


Third place has 4 choices because 1 number is filled in 2nd place. so 4 numbers.


Total  numbers lying between 100 and 1000 = 5 * 5 * 4

                                                                           = 100


Hope this helps!

                                                                  


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