How many numbers lying between 100 and 10000 can be formed with the digits 1, 2, 3, 4 and 5 if the digits in the same number are not repeated?
Answers
Step-by-step explanation:
Total number that can be created = 840
Step-by-Step Explanation: We need to find the number.
The numbers formed using digits 1, 3, 5, 6, 7, 8, 9 should be between 1000 and 10000, now the number between 1000 and 10000 is actually all 4 digits. , We need to find all 4 digits that can be created using the given digits 1, 3, 5, 6, 7, 8, 9, therefore, the ED numbers that can be created without repeating digits. 7 Number of Possibilities 4 Therefore, the total number that can be formed is = 7 x 6 x 5 x 4 = 840
Step-by-step explanation:
Total no. of 3 digit numbers formed=5×5×5=125
Total no. of 4 digit numbers =5×5×5×5=625
∴ Total numbers between 100 & 1000 formed =750.
Total number of 3 digit numbers without repetition=
5
P
3
No. of 4 digit numbers without repetition=
5
P
4
∴ No. of numbers between 100 & 1000 with at least one repeating digit=750−
5
P
3
−
5
P
4