How many numbers lying between 1000 and 10000 can be formed by using the digits 1,3,5,6,7,8,9 no digits being repeated?
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This is the requested number: ABCD As ABC is greater than 400 and less than 1000, we conclude that: 1. A can be one of 4, 5, 6.
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16
Answer:
Total numbers which can be formed = 840
Step-by-step explanation:
We need to find the no. of numbers formed by using the digits 1, 3, 5, 6, 7, 8, 9 and the numbers must lie between 1000 and 10000
Now, the numbers which lie between 1000 and 10000 are actually all 4 digits numbers
So, we need to find all 4 digit numbers that can be formed by using the given digits : 1, 3, 5, 6, 7, 8, 9
Therefore, The required numbers which can be formed without repetition of the digits :
No. of digits = 7
Number of possibilities = 4
So, Total numbers which can be formed = 7 × 6 × 5 × 4
= 840
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