Question

how many numbers of gold atom present in 0.6 gram of 18 carat gold .The24 carat gold is taken as 100 percent pure gold .​

Answer 1

Answer:-

1.38×10²¹ atoms

Explanation:-

Here, we are given with 0.6g of 18 carat gold.

As we know that 24 carat gold is taken as 100% pure gold, thus we can understand that in given 0.6g gold, 18 parts are pure gold and remaining 6 parts are other metals.

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So firstly, let's calculate the mass of pure gold in 0.6g.

⇒18/24 × 0.6

⇒0.75 × 0.6

⇒0.45g

Hence, 0.45g of pure gold is there in 0.6g of 18 carat gold.

• Molar mass of gold = 197 g/mol

Number of mole in 0.45g :-

= Given Mass/Molar mass

= 0.45/197

= 0.0023 mole

• Avogadro Number = 6.022×10²³

Number of atoms :-

= No of mole × Avogadro Number

= 0.0023×6.022×10²³

= 0.0138×10²³

= 1.38×10²¹ atoms

Thus, 1.38×10²¹ gold atoms are there.

Answer 2

Explanation:

Answer:-✍️

1.38×10²¹ atoms

Explanation:-

Here, we are given with 0.6g of 18 carat gold.

• As we know that 24 carat gold is taken as 100% pure gold, thus we can understand that in given 0.6g gold, 18 parts are pure gold and remaining 6 parts are other metals.

________________________________

So firstly, let's calculate the mass of pure gold in 0.6g.

⇒18/24 × 0.6

⇒0.75 × 0.6

⇒0.45g

• Hence, 0.45g of pure gold is there in 0.6g of 18 carat gold.

• Molar mass of gold = 197 g/mol

Number of mole in 0.45g :-

= Given Mass/Molar mass

= 0.45/197

= 0.0023 mole

• Avogadro Number = 6.022×10²³

Number of atoms :-

• = No of mole × Avogadro Number

= 0.0023×6.022×10²³

= 0.0138×10²³

= 1.38×10²¹ atoms

• Thus, 1.38×10²¹ gold atoms are there.

hope this helps you!!

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