Question

how many numbers of molecules are present in 10g of calcium carbonate?

Answer 1

weight is given = 10g
molecular mass of caco3 =100g
ATQ
molecular mass × mole = wieght
$100 \times mole = 10 \\ mole = \frac{10}{100} \\ mole = 0.1ans$
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Answer 2

No. Of molecules = no. Of moles * Avogadro's number ( 6.022 * 10^23)

No. Of moles = given mass / molar mass
Here, no. Of moles of CaCo3 = 10gm / 100 gm = 0.1 mol

Thus, no. Of molecules = 0.1 × 6.022 * 10^23 = 6.022 × 10^22