Question

how many numbers of the two digits are divisible by 7​

Answer 1

The first two digit number divisible by 7 = 14

last two digit number divisible by 7 = 98

so a = 14 and l = 98 where a = first term of A.P. and l = last term of A.P.

so our A.P. formed is 14 , ….. , …., .. , 98

formula for finding the no of terms in A.P =

l = a + (n-1) d

(d means difference between terms = 7)

so now put the values

i.e. 98 = 14 + (n - 1) 7

84 = 7n - 7

91 = 7n

n = 91/7 = 13

Therefore there are 13 two digit numbers divisible by 7



Mark it as brainliest answer

Answer 2

14 two digits numbers are divisible ok and the last no is divisible by 7 two digit is 98