Question

how many numbers of two digit numbers can be formed out of four digits p q,r,s?
a.6 b.11 c.12 d.13​

Answer 1

Answer:

The first digit can be one of p, q, r and s.

The second digit can be one of p, q, r and s, but not the one chosen as first digit.

The first digit has 4 possible values.

The second digit has 3 possible values.

The total combinations is  4∗3=12 .(option c)

Hope it helps... Please mark as the brainliest!!!

Answer 2

Step-by-step explanation:

HEY MATE YOUR ANSWER IS HERE ^_^

THERE ARE 4 DIGITS p,q,r,s.

WE HAVE TO FORM 2 DIGIT NUMBER

SO BY P AND C

THERE ARE $4C2 * 2!$ WAYS OF MAKING NUMBER.

THAT IS,

$\frac{4!}{2!*2!} * 2!$

$\frac{4!}{2!} = \frac{4*3*2*1}{2*1} = 12$

PLEASE MAKE ME A BRAINLIST ANSWER FOR THE QUESTION.