Math, asked by ayushmaddhesiya91, 7 months ago

How many numbers of two digits are divisible by 31

Answers

Answered by mukund75
1

Step-by-step explanation:

Answer:

First two digit number divisible by 3 = 12

Last two digit number divisible by 3 = 99

An arithmetic progression (A.P) is a progression in which the difference between two consecutive terms is constant.

A.P = 12,15,18,…,99

here

First term (a) = 12

Common difference (d) = 3

Let us consider there are n numbers then

an = 99

a + (n – 1)d = 99

12 + (n – 1)3 = 99

12 + 3n – 3 = 99

n = 29+1

n = 30

∴ Two digit numbers divisible by 3 = 30.

Answered by sheetall49
0

Answer:

two numbers,

62

93

Step-by-step explanation:

62/31=2

93/31=2

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