How many numbers of zeros are there in following expression 211 x 1253 x 711+ 311 x 711x 210 x 51+ 1112 x 213 x 5125
Answers
Answer:
To explain the solution we must know something about the nature of zeros, before doing this lets have a simple example, the number of zeros in the end of
10+100+1000+……………..+ 10000000000000000000 are 1 because we can take 10 common out of this expression and write it as 10(1+10+100+……………..+ 1000000000000000000) And clearly the term present inside the bracket has unit digit 1 which when multiplied with 10 results into 1 zero at its end.Thus number of zeros in any such expression will depend on the least zero holder in the expression.
Now using the same logic we can say least number of zeros will be contributed by second term i.e. 311 x 711x 210 x 51 as it contains only single power of 5 .Hence it contains only 1 zero, so the number of zeros for whole expression is 1 .