Question

how many numbers with 6 digit can be formed from digits 3,4,5,6,7,8 if no digit being repeated how many of these are a)divisible by 5 b)not divisible by 5​

Answer 1

Since the number should be divisible by 4 the last 2 digit must be one of the following :12,16,24,32,36,52,56,64=8 Possibilities.

The first 4 digits can be filled by the remaining 4 numbers in each case.

⇒ Permutations =8×

4

P

4

=8×4!=192.

Hence, the answer is 192.

Answer 2

Answer:

how many numbers with 6 digit can be formed from digits 3,4,5,6,7,8 if no digit being repeated how many of these are a)divisible by 5 b)not divisible by 5