How many numbers with 6 digits can be formed from the digits 3, 4, 5, 6, 7, 8 if no digit being repeated ? How many of these are
(a) divisible by 5?
(b) not divisible by 5?
Answers
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Answer:
(a) 120
(b) 600
Step-by-step explanation:
Hi,
We need to form 6 digit numbers using the digits
3,4,5,6,7 and 8 without repetition.
(a)
For a number to be divisible by 5, its last digit should be
5, So, if we fix 5 in units place and then permute the rest
of the 5 digit positions with remaining 5 digits which
can be done in 5! ways,
Hence,total number of numbers which are divisible by 5
are 5! = 120
(b)
Total number of numbers that can be formed from the
given digits are 6!, of which 5! are divisible by 5 from(a),
so the remaining 6! - 5! = 600 numbers will not be
divisible by 5.
Hope, it helps !
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