Question

How many numbers with distinct digits are possible whose products of digits is 28

Answer 1

Answer:

8

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Step-by-step explanation:

Since 28 = 4 × 7, two of the digits must be 4 and 7.

(We can't use 28 = 2 × 2 × 7 as the source of digits since the digits must be distinct.)

We can also throw in a 1 as an extra digit since that doesn't change the product.  (But only one 1 since the digits must be distinct.)

So there are 2 digits numbers and 3 digit numbers.

2 digit numbers:  47  74

3 digit numbers:  147  174  417  471  714  741

Total 8 number