Question

How many nunbrs are there between 103and751 which are divisible by 6

Answer 1

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a=108 as it is the nearest no divisible to 6 to 103

an= 750 as it is the nearest no divisible by 6 to 751

REST YOU MUST HAVE UNDERSTOOD

Answer 2

first no. divisible by 6 between 103 and 751 = 108
last no. divisible by 6 brtween 103 and 751 = 750

a = 108
an = 750
d= 6
n=?

an = a + ( n - 1 ) d
750 = 108 + ( n - 1 ) 6
(n - 1) 6 = 750 - 108
(n-1) = 642/6
n = 107 +1
n = 108

numbers divisible by 6 between 103 and 751 are = 108

i hope its help ☆☆ :)