HOW MANY O2 MOLECULES ARE PRESENT IN 0.02 MOLES OF THE GAS
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Answer:
12.044 × 10^21
Explanation:
let moles be n , no. of molecules be N and avagodra no. be N'
now
n= N/N'
nN' =N
n=0.02
N'= 6.022 × 10^23
N = 12.044 × 10^21
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