how many odd days are there in frist 75 years?
Answers
Answer:
1776 to 15.06. 1776) Counting of odd days: No of odd days in 1600 years = 0 No of odd days in 100 years = 5 75 years = 18 leap years + 57 ordinary years = 18*2 + 57*1 = 36 + 57 = 93 odd days = 13 weeks + 2 odd days = 2 odd days ∴ 1775 years have (0+5+2) = 7 odd days = 0 odd days.
75 years has 2 odd days.
Step-by-step explanation:
Counting of odd days.
- 1) Normal years = 365 days
= 52 weeks + 1 days.
∴ Therfore 1 ordinary years has 1 odd day
- 1 Leap year = 366 days
= 52 weeks + 2 days.
∴ Therefore 1 leap years has 2 odd days.
- 75 years = 18 leaps years + 57 ordinary years
= 18 × 2 + 57 × 1
= 36 + 57
= 93 Odd days
= 13 weeks + 2 days
∴ Therefore 75 years has 2 odd days.