How many odd days are there in one year and ten days ?
(A) Cannot be determined (B) Four (C) Five (D) Six
Answers
Odd days in ordinary year = (52 weeks + 1) days. Odd days in a leap year = (52 weeks +2) days. So odd days in 100 years will be (76 x 1 + 24 x 2) which is 124 odd days. This can also be written as 17 weeks + 5 days. So every 100 years will have 5 odd days. Similarly, 200 years will have (5 x 2) = 3 odd days and 300 years will have 1 day.
The number of odd days in 400 years will be ( 5 x 4 + 1) because 400 is itself a leap year and that is why it has one odd day extra. Thus odd days in 400 will be 0. This is same for every year which is a multiple of 100 and 400. Thus 1200 will also have odd days. Now we will solve some examples to have a better understanding of this, concept.
Please follow me and mark me as brainilist
Given : one year and ten days
To Find : odd days
Solution:
odd days are days left after complete number of weeks
or u can say remainder after dividing by 7
one year and ten days
For a normal year = 365 + 10 = 375 days
375 = 53 * 7 + 4
Hence odd days = 4 ( Four)
For a Leap year = 366 + 10 = 376 days
376 = 53 * 7 + 5
Hence odd days = 5 ( Five)
Hence A) Can not be determined ( until leap year information is available)
It would be (B) Four for a normal year
and (C) Five for a leap year
Learn More:
Convert 480 days into years step by step - Brainly.in
https://brainly.in/question/13399229