Math, asked by aaaaa73, 1 year ago

how many odd numbered pages are there in a book of 1089 pages​

Answers

Answered by REVEKAA
6

1089/2=544.5 = 545 (Approx.)

Answered by pulakmath007
2

There are 545 odd numbered pages are there in a book of 1089 pages

Given :

A book of 1089 pages

To find :

The number of odd numbered pages are there in a book of 1089 pages

Concept :

For an arithmetic progression

The nth term of an AP is

aₙ = a + (n - 1)d.

a = first term

aₙ = nth term

d = common difference.

Solution :

Step 1 of 3 :

Find the progression

A book of 1089 pages

We have to find number of odd numbered pages

The odd numbered pages are 1 , 3 , 5 , 7 , 9 , . . . . , 1089

This is an arithmetic progression

Step 2 of 3 :

Write down first term and common difference

The arithmetic progression is

1 , 3 , 5 , 7 , 9 , . . . . , 1089

First term = a = 1

Common Difference = d = 3 - 1 = 2

Step 3 of 3 :

Find the number of odd numbered pages

Let number of terms in the AP = n

Then nth term of the AP = 1089

a + (n - 1)d = 1089

⇒ 1 + (n - 1) × 2 = 1089

⇒ 1 + 2n - 2 = 1089

⇒ 2n - 1 = 1089

⇒ 2n = 1090

⇒ n = 1090/2

⇒ n = 545

∴ There are 545 odd numbered pages are there in a book of 1089 pages

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