how many odd numbered pages are there in a book of 1089 pages
Answers
1089/2=544.5 = 545 (Approx.)
There are 545 odd numbered pages are there in a book of 1089 pages
Given :
A book of 1089 pages
To find :
The number of odd numbered pages are there in a book of 1089 pages
Concept :
For an arithmetic progression
The nth term of an AP is
aₙ = a + (n - 1)d.
a = first term
aₙ = nth term
d = common difference.
Solution :
Step 1 of 3 :
Find the progression
A book of 1089 pages
We have to find number of odd numbered pages
The odd numbered pages are 1 , 3 , 5 , 7 , 9 , . . . . , 1089
This is an arithmetic progression
Step 2 of 3 :
Write down first term and common difference
The arithmetic progression is
1 , 3 , 5 , 7 , 9 , . . . . , 1089
First term = a = 1
Common Difference = d = 3 - 1 = 2
Step 3 of 3 :
Find the number of odd numbered pages
Let number of terms in the AP = n
Then nth term of the AP = 1089
a + (n - 1)d = 1089
⇒ 1 + (n - 1) × 2 = 1089
⇒ 1 + 2n - 2 = 1089
⇒ 2n - 1 = 1089
⇒ 2n = 1090
⇒ n = 1090/2
⇒ n = 545
∴ There are 545 odd numbered pages are there in a book of 1089 pages
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