Question

how many odd numbers less than 1000 can be formed using the digits 0,1,4,5,7,8 if repetition of digir is allowed

Answer 1

Answer:

HERE THE REQUIRED NUMBER= 12 + 6 + 3 = 21

Step-by-step explanation:

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Answer 2

Answer:

1 , 5 , 7 , 11 , 15 , 17 , 41 , 45 , 47 , 51 , 55 , 57 , 71 , 75 , 77 ,  81 , 85 , 87 , 101 , 105 , 107 , 111 , 115 , 117 , 141 , 145 , 147 , 151 , 155 , 157 , 171 , 175 , 177 , 181 , 185 , 187 , 401 , 405 , 407 , 411 , 415 , 417 , 441 , 445 , 447 , 501 , 505 , 507 , 511 , 515 , 517 , 541 , 545 , 547 , 551 , 555 , 557 , 571 , 575 , 577 , 581 , 585 , 587 , 701 , 705, 707 , 711 , 715 , 717 , 741 , 745 , 747 , 751 , 755 , 757 , 771 , 775 , 777 , 781 , 785 , 787 , 801 , 805 , 807 , 811 , 815 , 817 , 841 , 845 , 847 , 851 , 855 , 857 , 871 , 875 , 877

95 numbers can be made