how many of cu atoms are present in 127g of copper? (at mass 63.5g)
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From faraday's law of electrolysis, we get
W=Zit=
F
E
it
Where, W= Deposited amount
E= Equivalent weight
F=Faraday
i=Electricity passed
t= Time
⇒1.27=
96500
63.5
×2×t
⇒t=965 sec
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