Question

How many of ethanol should be mixed with 225 mL of water to get a 4.5% by volume mixture?

Answer 1

Answer:

Bonjour, mon ami!

If X is amount of ethanol you require

X/(225+X)= 4.5/100

(225+X )×4.5 =100X

(225+X)×45 =1000 X

45×225 + 45 X =1000 X

1000 X - 45 X = 45×225

955 X = 45×225

X = 45×225/955

X= 10.60 mL

Au revoir!