how many of the following numbers are divisible by 132 264,396,462,792,968,2178,5184,6336 and in the solution of this question why do we have taken the co prime factors( please be serious while answering the question )
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Step-by-step explanation:
132 = 4 x 3 x 11
So, if the number divisible by all the three number 4, 3 and 11, then the number is divisible by 132 also.
264 ⇒ 11, 3, 4 (/)
396 ⇒ 11, 3, 4 (/)
462 ⇒ 11, 3 (X)
792 ⇒ 11, 3, 4 (/)
968 ⇒ 11, 4 (X)
2178 ⇒ 11, 3 (X)
5184 ⇒ 3, 4 (X)
6336 ⇒ 11, 3, 4 (/)
Therefore the following numbers are divisible by 132 : 264, 396, 792 and 6336.
Required number of number = 4.
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