How many of the numbers formed are divisible by 3 ? why ?
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Since a five-digit number is formed by using digits 0,1,2,3,4 and 5, divisible by 3 i.e., only possible when the sum of digits is multiple of three which gives two cases.
Case I: Using digits 0,1,2,4,5 the number of ways =4×4×3×2×1=96.
Case II: Using digits 1,2,3,4,5 the number of ways =5×4×3×2×1=120
Therefore, total number formed =120+96=216.
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