how many of the numbers formed in a are divisible by 3? why?
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This combination can give 3*2*1 = 6 three-digit numbers. So, (4 + 4 + 4 + 4 + 6 + 6 + 6 + 6) = 40 three-digit numbers divisible by 3 can be formed by digits 0, 1, 2, 3, 4 and 5 without repetition. A number is divisible by if the sum of its digits is divisible by .
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This combination can give 3*2*1 = 6 three-digit numbers. So, (4 + 4 + 4 + 4 + 6 + 6 + 6 + 6) = 40 three-digit numbers divisible by 3 can be formed by digits 0, 1, 2, 3, 4 and 5 without repetition. A number is divisible by if the sum of its digits is divisible by .
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