how many of their 2 S o4 3 are required to prepare for l of 0.02 M solution
Answers
Answer:
Total volume of the solution is 2 L,
Mixture X contains 0.02 moles of [Co(NH
3
)
5
SO
4
]Br
Therefore Molarity of [Co(NH
3
)
5
SO
4
]Br,
Volume of solution in Litres
No. of moles of solute
=
2
0.02
=0.01M
Mixture of X also contains 0.02 moles of [Co(NH
3
)
5
Br]SO
4
,
Therefore, Molarity of [Co(NH
3
)
5
Br]SO
4
=
Volume of solution in Litres
No. of moles of solute
=
2
0.02
=0.01M
Now, according to the reaction,
(0.01M)
[Co(NH
3
)
5
SO
4
]Br
+AgNO
3
→[Co(NH
3
)
5
SO
4
]NO
3
(Soluble)+
[Y]ppt
AgBr
↓
According to Avogadro law, the molarity of AgBr will also be 0.01, since molarity is moles per litre. Therefore, the number of moles of AgBr will also be 0.01.
Similarly in the second reaction, BaSO
4
(Z) will be precipitated and [Co(NH
3
)
5
Br]Cl
2
will be formed which is soluble. Therefore, no. of moles of BaSO
4
= 0.01
Explanation:
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