How many optically active stereoisomers are possible for butane 2 3 diol?
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Solution : Butane -2,3 diol CH3−CH(OH)−CH(OH)−CH3 has two chiral centers. Hence theoretically there must be 2n=22=4 enthronements possible. However one of the configuration has plane of symmetry and hence is optically in active.
Answered by
1
4
Solution : Butane -2,3 diol CH3−CH(OH)−CH(OH)−CH3 has two chiral centers. Hence theoretically there must be 2n=22=4 enthronements possible. However one of the configuration has plane of symmetry and hence is optically in active.
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