How many orbitals are there in n+l whose electonic configuration is greater than 6 and less than 8? Explain?
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Hi____________
6<7<8
suppose we have 7 electron
n = orbital quantum no
l= azimuthal q.no
n+l=3
bcz here n=2
and l for p shell=1
hope it help
6<7<8
suppose we have 7 electron
n = orbital quantum no
l= azimuthal q.no
n+l=3
bcz here n=2
and l for p shell=1
hope it help
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Answered by
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ur clearly answer in the image of Mr Green...
6<7<8
...suppose we have 7 electron
n=orbital quantum no
l = azimuthal Q.no
n+1=3
because here n= 2
and l for p shell =1
.........may ...be....help.....ful...
6<7<8
...suppose we have 7 electron
n=orbital quantum no
l = azimuthal Q.no
n+1=3
because here n= 2
and l for p shell =1
.........may ...be....help.....ful...
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