Question

how many ordered pairs of (x,y) integers satisfy x/15=36/y​

Answer 1

infinite

x=2.4y

we can substitute any number in place of x or y

Answer 2

Answer:

(270,2) ,(-270,-2) , (540,1) , (-540,-1)

Step-by-step explanation:

x/15=36/y. or. y=540/x

On putting x=+/-1 ,+/-2,+/-3,+/-4, +/-5 ,+/-6 , +/-9 , +/-10 , +/-12 , +/-15 , +/-18 , +/-20 , +/-27 , +/-30 , +/-36 , +/-45 , +/-54 , +/-60 , +/-90 , +/-108 , +/-135 , +/-180 , +/-270 and. +/-540.

Thus , 48 ordered pairs are :-

(1,540) , (-1,-540) , (2,270) , (-2,-270) , (3,180) , (-3 , -180) , (4,135) , (-4,-135)………

…………………………………., (270,2) ,(-270,-2) , (540,1) , (-540,-1). Answer.