Question

How many ounce of pure acid must be added to 20 ounces of a solution that is 5% acid to strengthen it to a solution that is 24% acid?? ​

Answer 1

Answer:

in 20 ounces acid = 20*5/100 = 1

let , x added

A/q,

(x+1)*100/(20+x) = 24

100x+100 = 480 + 48x

52x = 380

x = 7.30 (approx) (Ans)

[ mark as brainlist if you understand my solution]