how many ounces of pure acid must be added to 20 ounces of a solution that is 5% acidic to strengthen it to a solution that is 24% acidic
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8
Initially
The total mass = 20 oz
=> Mass of acid = 1/20 * 20 oz = 1 oz
=>Mass of water = 19 oz
Now lets add x oz of acid
Total volume of acid is (1 + x) oz
Total mass of solution = (20 + x) oz
Concentration = 24#
=> 0.24 = (1+x)/(20+x)
Solving for x you get
x = 5
Therefore 5 oz of pure acid must be added
The total mass = 20 oz
=> Mass of acid = 1/20 * 20 oz = 1 oz
=>Mass of water = 19 oz
Now lets add x oz of acid
Total volume of acid is (1 + x) oz
Total mass of solution = (20 + x) oz
Concentration = 24#
=> 0.24 = (1+x)/(20+x)
Solving for x you get
x = 5
Therefore 5 oz of pure acid must be added
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5 oz of pure acid must be added
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