Question

how many oxygen atom are present in 50g caco3​

Answer 1

Answer:

50g CaCo3= 9.0333× 10^23

Explanation:

Molecular weight of CaCo3 =40+12+3×16

=100g

100g of CaCo contain = 3×6.022×10^23 atom of Oxygen

therefore ...

50g CaCo3 will contain=

= 3×6.022×10^×50/100

• = 9.033×10^23 atoms of Oxygen