How many oxygen atoms are in 2.71 × 10^25 molecules of CO2
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Answered by
15
Answer:
54.2 × 10²⁴ atoms of Oxygen are present.
Explanation:
In 1 molecule of CO2, 2 atoms of O2 are present.
Therefore in 2.71 × 10^25 molecules of CO2,
2.71 × 10^25 × 2 atoms of O2 are present
Answer = 54.2 × 10²⁴
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1
Explanation:
In the decomposition of lead (II) nitrate to give lead (II) oxide, nitrogen dioxide and oxygen gas, the coefficient of nitrogen dioxide (in the balanced equation) is:
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